WebFeb 9, 2024 · Sum of squares of first n natural numbers means sum of the squares of the given series of natural numbers. Sum of squares of n natural numbers can be calculated using the formula [n (n+1) (2n+1)] / 6. Let n be a natural number. Squaring the number is … WebIf the mean of the squares of first n natural numbers is 105, then the median of first n natural numbers is A 8 B 9 C 10 D 11 Medium Solution Verified by Toppr Correct option is B) We know mean of the squares of first n natural number is, = n1 2+2 2+...+n 2=105 ... (Given) ⇒ 6(n+1)(2n+1)=105 ⇒2n 2+3n−629=0 ⇒(2n+37)(n−17)=0 ⇒n=17
The average of first 50 natural numbers is - Toppr
WebThe A.M. of first n even natural number is A n(n+1) B 2n+1 C 2n D n+1 Medium Solution Verified by Toppr Correct option is D) A.M.= n2+4+.....+2n= n2(1+2+.....+n)= 2n2n(n+1)=n+1 Ans: D Was this answer helpful? 0 0 Similar questions Find the sum of first n terms of the series. 1 3+3×2 2+3 3+3×4 2+5 3+3×6 2+.... If n is even. Medium View solution > WebIf the arithmetic mean of first n natural numbers is 15, then n is equal to: A 15 B 20 C 14 D 29 Medium Solution Verified by Toppr Correct option is D) The first n natural numbers are 1,2,3,...,n Given that mean of n natural numbers is 15 n1+2+3+...+n=15 ——— (1) We know that sum of first n natural numbers is 2n(n+1) 1+2+3+...+n= 2n(n+1) ——— (2) buckboard\\u0027s 0h
If the mean of first n natural numbers is 5n/9, then n - Brainly
WebThe first 10 natural numbers are 1 to 10. Sum of first n natural numbers = n(n+1) 2 here, n = 10 So, sum of first 10 natural numbers = 10(10+1) 2 = 10×11 2 = 55 Mean = Sum of first … WebThe mean of first n natural numbers is calculated as follows. Sum of all observations / Number of observations. = [n (n + 1)/2]/n. = (n + 1)/2. Variance, (σ²) = 1/n ∑ ni = 1 (x i - x )². … WebDec 20, 2024 · 1. The mean of the first n natural number is (5n/9). 2. Let 1, 2, 3, ..., n be n consecutive natural numbers. => The sum of the first n natural numbers ( Consecutive ) is given by the formula = (n) (n+1)/2. 3. Let X1, X2, X3, X4, ..., Xn be n terms. The average of the n terms if given by the formula, => Average = (X1 + X2 + X3 +... Xn)/n. extension cord in rain